Can someone help me with my algebra homework?

Problem- f(r) = square root of (25-25-2x) -6





originally it was like this : f(r) = square root of (25-r)-6





and one of the problems that went along with that was:


f(25-2x)





So I no i need to plug that in, but I don't understand how to with the square root. Can someone help please?Can someone help me with my algebra homework?
f(r) = sqrt(25-r)-6





Then





f(25-2x) = sqrt[25-(25-2x)] - 6 = sqrt[25-25+2x)] - 6 =





= sqrt(2x) - 6





and there is nothing you can do more.

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